2x^2-4x+4=2

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Solution for 2x^2-4x+4=2 equation: 



2x^2-4x+4=2

We move all terms to the left:

2x^2-4x+4-(2)=0

We add all the numbers together, and all the variables

2x^2-4x+2=0

a = 2; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{4}=1$

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